Class SchemaRDD

x.__init__(...) initializes x; see help(type(x)) for signature

Overrides: object.__init__

(inherited documentation)

Save the contents as a Parquet file, preserving the schema.

Files that are written out using this method can be read back in as a SchemaRDD using the SQLContext.parquetFile method.

>>> import tempfile, shutil
>>> parquetFile = tempfile.mkdtemp()
>>> shutil.rmtree(parquetFile)
>>> srdd = sqlCtx.inferSchema(rdd)
>>> srdd.saveAsParquetFile(parquetFile)
>>> srdd2 = sqlCtx.parquetFile(parquetFile)
>>> sorted(srdd2.collect()) == sorted(srdd.collect())
True

Registers this RDD as a temporary table using the given name.

The lifetime of this temporary table is tied to the SQLContext that was used to create this SchemaRDD.

>>> srdd = sqlCtx.inferSchema(rdd)
>>> srdd.registerAsTable("test")
>>> srdd2 = sqlCtx.sql("select * from test")
>>> sorted(srdd.collect()) == sorted(srdd2.collect())
True

Inserts the contents of this SchemaRDD into the specified table.

Optionally overwriting any existing data.

Return the number of elements in this RDD.

Unlike the base RDD implementation of count, this implementation leverages the query optimizer to compute the count on the SchemaRDD, which supports features such as filter pushdown.

>>> srdd = sqlCtx.inferSchema(rdd)
>>> srdd.count()
3L
>>> srdd.count() == srdd.map(lambda x: x).count()
True

Overrides: rdd.RDD.count

Persist this RDD with the default storage level (MEMORY_ONLY).

Overrides: rdd.RDD.cache

(inherited documentation)

Set this RDD's storage level to persist its values across operations after the first time it is computed. This can only be used to assign a new storage level if the RDD does not have a storage level set yet.

Overrides: rdd.RDD.persist

(inherited documentation)

Mark the RDD as non-persistent, and remove all blocks for it from memory and disk.

Overrides: rdd.RDD.unpersist

(inherited documentation)

Mark this RDD for checkpointing. It will be saved to a file inside the checkpoint directory set with SparkContext.setCheckpointDir() and all references to its parent RDDs will be removed. This function must be called before any job has been executed on this RDD. It is strongly recommended that this RDD is persisted in memory, otherwise saving it on a file will require recomputation.

Overrides: rdd.RDD.checkpoint

(inherited documentation)

Return whether this RDD has been checkpointed or not

Overrides: rdd.RDD.isCheckpointed

(inherited documentation)

Gets the name of the file to which this RDD was checkpointed

Overrides: rdd.RDD.getCheckpointFile

(inherited documentation)

Return a new RDD that is reduced into `numPartitions` partitions. >>> sc.parallelize([1, 2, 3, 4, 5], 3).glom().collect() [[1], [2, 3], [4, 5]] >>> sc.parallelize([1, 2, 3, 4, 5], 3).coalesce(1).glom().collect() [[1, 2, 3, 4, 5]]

Overrides: rdd.RDD.coalesce

(inherited documentation)

Return a new RDD containing the distinct elements in this RDD.

>>> sorted(sc.parallelize([1, 1, 2, 3]).distinct().collect())
[1, 2, 3]

Overrides: rdd.RDD.distinct

(inherited documentation)

Return the intersection of this RDD and another one. The output will not contain any duplicate elements, even if the input RDDs did.

Note that this method performs a shuffle internally.

>>> rdd1 = sc.parallelize([1, 10, 2, 3, 4, 5])
>>> rdd2 = sc.parallelize([1, 6, 2, 3, 7, 8])
>>> rdd1.intersection(rdd2).collect()
[1, 2, 3]

Overrides: rdd.RDD.intersection

(inherited documentation)

Return a new RDD that has exactly numPartitions partitions.

Can increase or decrease the level of parallelism in this RDD. Internally, this uses a shuffle to redistribute data. If you are decreasing the number of partitions in this RDD, consider using `coalesce`, which can avoid performing a shuffle. >>> rdd = sc.parallelize([1,2,3,4,5,6,7], 4) >>> sorted(rdd.glom().collect()) [[1], [2, 3], [4, 5], [6, 7]] >>> len(rdd.repartition(2).glom().collect()) 2 >>> len(rdd.repartition(10).glom().collect()) 10

Overrides: rdd.RDD.repartition

(inherited documentation)

Return each value in self that is not contained in other.

>>> x = sc.parallelize([("a", 1), ("b", 4), ("b", 5), ("a", 3)])
>>> y = sc.parallelize([("a", 3), ("c", None)])
>>> sorted(x.subtract(y).collect())
[('a', 1), ('b', 4), ('b', 5)]

Overrides: rdd.RDD.subtract

(inherited documentation)