What is the reason for show-paren-delay to have a default value of
0.125?
reddit / emacs

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biggrben · 2022-07-07 17:34

`C-h v show-paren-delay` shows that the default value is `0.125`.

But why is it `0.125`? What is the purpose of this delay?

I realize that I find it more comfortable to type Elisp code when its
value is set to `0` and that makes me wonder if there is a reason for
it to have `0.125` by default.

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alternateved · 2022-07-07 17:46

`delete-pair-blink-delay` is even better

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MitchellMarquez42 · 2022-07-07 18:20

Might be a performance thing from the past or for lisp with a lot of
closing parentheses right next to each other.

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00-11 · 2022-07-07 18:40

Less distracting (than a shorter value) when you move around?

A default is just that - something that's expected (by Emacs dev) to
be better for more people in more contexts (for whatever
reason/"better"). Luckily, it's a user *option*.

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ieure · 2022-07-07 18:43

It's a debounce timer to improve performance when you move point
through several parens in nested lists.  If you have `((((` and step
one character at a time, it has to highlight four different times.
The debounce allows Emacs to skip that work and only highlight once
point comes to a stop for .125 seconds, which correlates with stopping
moving around and sitting there reading the code -- which is when the
highlight is most useful.

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emacs_expert · 2022-07-07 20:42

> delete-pair-blink-delay

Mind explaining what this is for? The Emacs help buffer for it wasn't
useful to me.

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alternateved · 2022-07-07 20:45

When you put point on opening parentheses an run `M-x delete-pair`, it
will jump to closing parentheses, wait a second and delete that pair
(or unwrap that balanced expression). This variable sets the waiting
time.

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Aaronzinhoo · 2022-07-07 21:04

I’ve always noticed this and now I’m reducing this value… lol thank
you for showing me this!