b2d
Subj : Re: Windows Prompt Runtimes SHORT-Debug
To   : borland.public.cpp.borlandcpp
From : Jeremy Pham
Date : Mon Jun 21 2004 06:59 am

"Ed Mulroy [TeamB]" <dont_email_me@bitbuc.ket> wrote:
>The situation is this:
>
>When your program is run it requests that Windows create a console
>window.  Windows does that and your program runs.  When your program
>finishes the console window is requested to close.  This is normal
>operation.
>
>You wish for the window to stay open until you are finished looking at
>the console window.  To do that your program must pause until you are
>ready for it to close.
>
>The method Mr Salzman provided works well.  CONIO.H must be included
>to provide the function prototype for getch.  That does not mean
>STDIO.H should be removed.
>
>Since you do not like getch() here are two other methods to achieve
>similar results.
>
>- Place this on the line immediately before the return statement in
>main
>      getchar();
>  It might be better if done in this way
>      printf("Press Enter ... ");
>      getchar();
>
>- place a breakpoint on the return statement in main
>
>.  Ed

Man, too bad I'm not expert.  I did some revisions and prompt is still short.  I'll need help revising.  Here's the first program:

#include <stdio.h>

main()
{
	int num1, num2;

	printf("Enter two integers, and I will tell you\n");
   printf("the relationships they satisfy: ");
   scanf("%d%d", &num1, &num2);

   if (num1 == num2)
   	printf("%d is equal to %d\n", num1, num2);

   if (num1 != num2)
   	printf("%d is not equal to %d\n", num1, num2);

   if (num1 < num2)
   	printf("%d is less than %d\n", num1, num2);

   if (num1 > num2)
   	printf("%d is greater than %d\n", num1, num2);

   if (num1 <= num2)
   	printf("%d is less than or equal to %d\n", num1, num2);

   if (num1 >= num2)
   	printf("%d is greater than or equal to %d\n", num1, num2);

   return 0;
}

Here's the second revision:

#include <stdio.h><conio.h>

main()
{
	int num1, num2;

	printf("Enter two integers, and I will tell you\n");
   printf("the relationships they satisfy: ");
   scanf("%d%d", &num1, &num2);

   if (num1 == num2)
   	printf("%d is equal to %d\n", num1, num2);

   if (num1 != num2)
   	printf("%d is not equal to %d\n", num1, num2);

   if (num1 < num2)
   	printf("%d is less than %d\n", num1, num2);

   if (num1 > num2)
   	printf("%d is greater than %d\n", num1, num2);

   if (num1 <= num2)
   	printf("%d is less than or equal to %d\n", num1, num2);

   if (num1 >= num2)
   	printf("%d is greater than or equal to %d\n", num1, num2);

   printf("Press enter...");
   getchar();

   return 0;
}

Yeah, this thing still runs short.  Can you help me revise?  Once again guys, thanks a lot for the help.

Thanks,
Jeremy Pham

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