[HN Gopher] BB(6) Is Hard (Antihydra) (2024)
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BB(6) Is Hard (Antihydra) (2024)
Author : Fibra
Score : 32 points
Date : 2025-07-13 17:30 UTC (4 days ago)
(HTM) web link (www.sligocki.com)
(TXT) w3m dump (www.sligocki.com)
| gliptic wrote:
| Recent developments on BB(6) previously posted here:
| https://scottaaronson.blog/?p=8972
| cubefox wrote:
| 272 points by bdr 18 days ago | 223 comments
|
| https://news.ycombinator.com/item?id=44406171
| _alternator_ wrote:
| Cool link, despite being a bit later than some of the other stuff
| on BB(6). Basically, it shows a 6-state Turing machine can encode
| a Collatz-type iteration:
|
| ``` a,b=8,0 while b!=-1: b+=2-a%2*3 a+=a>>1 ```
|
| Showing that these halt or not are long-standing open problems,
| so knowing upper bounds BB(6) would immediately solve them
| (modulo a lot of compute time).
| thrance wrote:
| See also: https://en.wikipedia.org/wiki/Chaitin%27s_constant
|
| A number, that if known, would allow us to derive the truth
| value of any statements from it.
| tromp wrote:
| only the truth of finitely refutable conjectures...
| david_for_you wrote:
| Hm, I'm not sure I would say that knowing an upper bound would
| be any help in solving these open problems, unless the way to
| prove that upper bound would involve a collatz type problem. We
| already know from the lower bound of BB(6) that we cannot
| iterate that far in this universe.
| _alternator_ wrote:
| An upper bound U for BB(6) implies that any program that runs
| longer than U never terminates. Thus the specific Collatz-
| type problems that can be encoded in 6 instructions can be
| run U+1 steps and if they don't halt, they won't halt.
|
| The proof that BB(6) is relevant is that you can encode it in
| a 6 instruction program, which is what the link does.
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