[HN Gopher] Orders of Infinity
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Orders of Infinity
Author : matt_d
Score : 51 points
Date : 2025-05-04 17:55 UTC (5 hours ago)
(HTM) web link (terrytao.wordpress.com)
(TXT) w3m dump (terrytao.wordpress.com)
| singularity2001 wrote:
| Since we know that these hyper real numbers are well defined we
| can teach them axiomatically to high school students the way
| Leibniz used them (and keep the explicit construction via filters
| to university students just like with a dedekind cut for reals)
|
| Here is the axiomatic approach in Julia and Lean
| https://github.com/pannous/hyper-lean
| btilly wrote:
| I'm not a big fan of using nonstandard analysis for this. We're
| assuming the existence of arbitrary answers that we cannot ever
| produce.
|
| For example, which function is eventually larger than the other?
| (1 + sin(x)) * e^x + x (1 + cos(x)) * e^x + x
|
| In the ultrafilter, one almost certainly will be larger. In fact
| the ratio of the two will, asymptotically, approach a specific
| limit. Which one is larger? What is the ratio? That entirely
| depends on the ultrafilter.
|
| Which means that we can accept the illusionary simplicity of his
| axiom about every predicate P(N), and it will remain simple right
| until we try to get a concrete and useful answer out of it.
| JohnKemeny wrote:
| I don't think that's the case. They can both _not have the
| property that it is eventually larger than the other_.
| LegionMammal978 wrote:
| The axioms demand that either one function is eventually
| dominated by the other, or both functions are of the same
| order. But which of these is the case will strongly depend on
| which subsequence you look at.
| btilly wrote:
| No, it is the case.
|
| Look for the comment in the article, _after passing to a
| subsequence if necessary_. The ultrafilter produces the
| necessary subsequence for any question that you ask, and will
| do so in such a way as to produce logically consistent
| answers for any combination of questions that you choose.
|
| That is why the ultrafilter axiom is a weak version of
| choice. Take the set of possible yes/no questions that we can
| ask as predicates, such that each answer shows up infinitely
| often. The ultrafilter results in an arbitrary yet consistent
| set of choices of yes/no for each predicate.
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