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Quartz crystals
Pieter-Tjerk de Boer, PA3FWM web@pa3fwm.nl
(This is an adapted version of part of an article I wrote for the
Dutch amateur radio magazine Electron, August 2016.)
[some quartz crystals] Quartz crystals have been used in radio
technology since the 1920s, to build very stable oscillators and to
filter signals. In WW2 they started to be mass-produced, as is very
nicely documented in [1], back then based on natural quartz from
Brazil. Nowadays quartz crystals are still a mass product (more than
2 billion per year, according to Wikipedia), most of which spend
their lives humbly clocking a microprocessor. But the importance of
even that task should not be underestimated: according to [2] a train
crashed in 1972 due to a badly designed crystal oscillator
spontaneously jumping to its third overtone.
Such a crystal is nothing more than a slice of quartz, sawn under the
right angle from a (nowadays synthetic) crystal, with an electrode on
both sides. The picture shows two common crystals with frequencies of
a few MHz; usually such crystals are in metal enclosures, but
sometimes one encounters these glass versions. These crystals use the
so-called thickness-shear vibration, in which both surfaces of the
crystal plate shift w.r.t. each other, as sketched at the right. The
two crystals above are much larger and resonate at lower frequencies,
alternately getting longer and shorter. There are also crystals which
resonate by bending like a tuning fork; among others the small 32.768
kHz crystals in watches work like this.
[equivalent circuit] The next figure shows the well-known equivalent
circuit of a crystal, with in blue typical values for a 10 MHz
crystal. The inductance L[m] and the capacitance C[m] are called the
"motional inductance" and "motional capacitance", because they are
directly related to the motion of the crystal (as will be discussed
further down the page). C[p] is the parallel capacitance: the
electrodes on the crystal form a small capacitor. And R[m] is a
resistor which represents the losses (due to friction etc.). The
frequency on which the series circuit of L[m] and C[m] resonates is
called the series resonance: at this frequency the crystal has a very
low impedance, practically only R[m] (with C[p] in parallel, but that
has little effect). In contrast, the impedance becomes very high at
the parallel resonance frequency: there L[m] resonates with the
series circuit of C[m] and C[p] connected in parallel to it. Their
total capacitance is slightly less than C[m] alone, so the parallel
resonance frequency is a little higher than the series resonance. In
practice, parallel to C[p] there is the capacitance of the circuit to
which the crystal is connected, which does not have an influence on
the series resonance, but does affect the parallel resonance. That is
why crystals for parallel resonance are always specified for a
specific extra parallel capacitance; in this example, 25 pF is needed
to bring the crystal to 10.000 MHz, as shown in dotted lines.
How does a quartz crystal resonate?
At first, the answer to this question is simple: quartz is slightly
elastic, so it can vibrate in the same way e.g. a rubber band or
guitar string can vibrate. You start with pulling the rubber band
from its neutral position. Due to this deformation, a force arises in
the elastic material which tries to undo the deformation. Next, you
let go of the rubber band. The material starts to move towards its
neutral position, the force decreases and becomes zero when the
neutral position is reached. By then however, the material is in
motion at some speed and will "overshoot" to the other side of the
neutral position. The elastic force will work against this, and so
on. We typically don't imagine a crystal as elastic, but the
principle is the same. Only the force becomes very large already at a
very small deformation, so the vibration will be much faster (higher
frequency) than with a rubber band.
[equivalent circuit] However, in a quartz crystal there are not just
mechanical effects as discussed above; due to the piezo-electric
effect, also electric effects play a role. On both sides of the
crystal there's a metal layer, between which a voltage can exist, and
/or on which a charge can accumulate. The relationship is illustrated
in the figure. We see the crystal as a "black box", with two kinds of
"input" at the left and two kinds of "output" at the right. The
inputs are how much the crystal is deformed, and how much electrical
charge has been put onto the connection plates. The outputs are the
force in the crystal which acts against the deformation, and the
electrical voltage we measure across the crystal. How these outputs
depend on the inputs is determined by physical properties of the
crystal, and is indicated in the figure.
B.t.w., this model is not the only possibility. One can also choose
different combinations of input and output, e.g., take the force as
input and the resulting deformation as the output, and there is also
some freedom in the choice of plus and minus signs (i.e., which
direction is denoted positive). But the model as shown here, is the
handiest for explaining the resonance.
Let's first assume that there is no charge on the crystal. The
crystal is not connected to anything, but we do deform it. We see
that that deformation causes two effects: a mechanical force and and
an electric voltage. That mechanical force gets a minus sign,
indicating that it works against the deformation.
Let's next assume that we have not deformed the crystal, but using an
electrical current we have put some charge on the electrodes. We see
that also in this case there will be an electical voltage and a
mechanical force. The electrical voltage should not surprise us: the
whole thing looks like a capacitor, and when charge is fed to a
capacitor, a voltage develops across it. The mechanical force is the
piezo-electric effect, and causes the crystal to "want" to deform
itself.
What happens if we apply alternating current? By the above
argumentation, there will be an alternating mechanical force in the
crystal. If the frequency is very high, that force is not capable of
significantly moving the crystal, due to its inertia: the deformation
remains nearly zero. Electrically the whole thing then still works as
a capacitor: C[p] in the equivalent circuit.
If the alternating current has a very low frequency, the crystal can
start moving due to the piezo-effect's mechanical force: the crystal
will be deformed. That deformation in turn will again cause an
electric voltage and a mechanical force. Due to the plus/minus signs
in the figure this effect is such that both the electrical voltage
and the mechanical force will be smaller in total than when there was
no deformation. Thus, we see that at low frequencies the same amount
of charge results in a lower voltage than at higher frequencies: the
thing still behaves as a capacitor, but with a (slightly) higher
capacitance. That matches the equivalent circuit: for low frequencies
the inductor does nothing, so C[m] and C[p] are in parallel.
Next, consider the crystal with nothing connected to it. We deform it
a little bit and then let go. The mechanical force tries to undo the
deformation, but due to inertia the deformation "overshoots" in the
opposite direction, which again will be counteracted by the elastic
force, and so on: the crystal vibrates mechanically on its own
resonant frequency. The deformation alternates between positive and
negative values, and according to the figure this also leads to an
alternating voltage across the crystal. All of this happens without
us applying any charge, i.e., without any electrical current. So
there is an AC voltage, but no current: on this frequency apparently
the crystal has a high impedance: it's the parallel resonance.
Finally, consider the situation in which we short-circuit the crystal
electrically, again apply an initial deformation, and let go. The
short circuit (direct wire between the crystal's metal plates)
ensures that no voltage can develop across the crystal. As soon as a
voltage "tries" to arise due to deformation and the piezo-effect, a
current will flow and transport charge from one plate to the other.
That charge in turn also causes a voltage, and the system will
constantly search for an equilibrium in which just so much charge is
displaced that the total voltage is 0 (because no voltage can exist,
due to the short-circuit connection). But that displaced charge in
turn also causes a contribution to the mechanical force, and
according to the plus/minus signs in the figure that force will be
opposite to the elastic force that is caused by the deformation
itself. Thus, the net effect of short-circuiting the crystal is that
the crystal is pushed slightly "less strongly" back to its neutral
state, and thus that the crystal resonates at a lower frequency than
without the short circuit. At this frequency there is no voltage
across the crystal, while there is a non-zero current: that's a low
impedance. This is the series resonance.
Thus, we see how the mechanical resonance of the crystal can be
recognized in how its impedance depends on the frequency, and how the
mechanical resonance moves to a slightly different frequency when we
short-circuit the crystal.
References:
[1] Youtube movie: Crystals go to war
[2] https://web.archive.org/web/20090312102803/http://www.edn.com/
article/CA6636507.html
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Text and pictures on this page are copyright 2016, P.T. de Boer,
web@pa3fwm.nl .
Republication is only allowed with my explicit permission.