Equation Icon  2∕3 2− 1 −4∕3 ⟨ω˙⟩ = 6 πfb(2πmfb ) (1 − e ) 𝒫𝒢 , (82 ) γ′ = e (2πf )−1(2πmf )2∕3m2-𝒢 −1∕3(α ∗+ 𝒢 m2- + κ∗η∗), (83 ) b b m 2 m 1 2 192 π 5∕3 ′ 2 P˙b = − --5--(2π ℳfb ) F (e) − 4π(2π μfb)ξ𝒮 G(e), (84 )