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# `bisect` — Array bisection algorithm

This module provides support for maintaining a list in sorted order without having to sort the list after each insertion. For long lists of items with expensive comparison operations, this can be an improvement over the more common approach. The module is called `bisect` because it uses a basic bisection algorithm to do its work. The source code may be most useful as a working example of the algorithm (the boundary conditions are already right!).

The following functions are provided:

`bisect.``bisect_left`(list, item[, lo[, hi]])
  Locate the proper insertion point for item in list to maintain sorted order. The parameters lo and hi may be used to specify a subset of the list which should be considered; by default the entire list is used. If item is already present in list, the insertion point will be before (to the left of) any existing entries. The return value is suitable for use as the first parameter to `list.insert()`. This assumes that list is already sorted.

`bisect.``bisect_right`(list, item[, lo[, hi]])
  Similar to `bisect_left()`, but returns an insertion point which comes after (to the right of) any existing entries of item in list.

`bisect.``bisect`(...)
  Alias for `bisect_right()`.

`bisect.``insort_left`(list, item[, lo[, hi]])
  Insert item in list in sorted order. This is equivalent to `list.insert(bisect.bisect_left(list, item, lo, hi), item)`. This assumes that list is already sorted.

`bisect.``insort_right`(list, item[, lo[, hi]])
  Similar to `insort_left()`, but inserting item in list after any existing entries of item.

`bisect.``insort`(...)
  Alias for `insort_right()`.

## Examples

The `bisect()` function is generally useful for categorizing numeric data. This example uses `bisect()` to look up a letter grade for an exam total (say) based on a set of ordered numeric breakpoints: 85 and up is an ‘A’, 75..84 is a ‘B’, etc.

    >>> grades = "FEDCBA"
    >>> breakpoints = [30, 44, 66, 75, 85]
    >>> from bisect import bisect
    >>> def grade(total):
    ...           return grades[bisect(breakpoints, total)]
    ...
    >>> grade(66)
    'C'
    >>> map(grade, [33, 99, 77, 44, 12, 88])
    ['E', 'A', 'B', 'D', 'F', 'A']

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