Subj : Getting an /48, /56 or /64 IPv6 address range
To   : Bj”rn Felten
From : Alexey Vissarionov
Date : Sun Aug 14 2016 19:19:00

Good ${greeting_time}, Bj”rn!

14 Aug 2016 16:37:20, you wrote to Michiel van der Vlist:

 MvdV>> It can't be because of a shortage of IPv6 addresses, so the only
 MvdV>> reason I can think of is that they want to charge extra for a /56
 MvdV>> or a /48.
 BF> Which is quite unbelievable. Even a /64 should be more than enough to
 BF> get every single gadget a person owns, its own unique IPv6 address.
 BF> After all it's an entire IPv4 range, isn't it (or am I'm thinking
 BF> wrongly here)?

Bwa-ha-ha-ha... You are absofu*****lutely wrong here.

I have /64 routed to me. That means, I can split it to 4294967296 subnets of size /96, each having 4294967296 addresses - as much as the whole IPv4.

And that's exactly what I do :-)

Once I'd get IPv6 from another ISP, I'd simply get another /64 subnet routed here and assign alternative addresses to my hardware. Anyway, they use fe80::1 for their default route to outer world.

 BF> I guess they've managed to trick their customers into thinking that
 BF> whatever more you get, the more valuable it is...

IPv6 isn't IPX: it doesn't have fixed number of bits for a network and host (those were 32 and 48, IIRC) - instead, it uses CIDR and allows routing of single /128 hosts as well as subnets of any size.


--
Alexey V. Vissarionov aka Gremlin from Kremlin
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