Subj : Relay6 To : Michiel van der Vlist From : Bj”rn Felten Date : Sun Nov 23 2014 23:27:19 MvdV> Where is Relay6 going to get the IPv6 address from to convert the call MvdV> to an IPv6 outgoing call? The same way your binkp mailer does, looking it up. And *that* part works. But it gets the error I tried to describe when trying to start a protocol transfer. From the help file (if someone can decipher it): /t:xxx tunnel binds on ip xxx (name/ip) (default any) this option is like the /b option, but on outgoing packets (to the remoteHost): we choose through which interface packets will go out by specifying an IPv* address. Obviously we must own this address. We set up the source address of our IPv* packets: by this way, together with the routing table, we decide the route of our packets. If we have two tunnel brokers, to use the first we'll mark packets with its IPv* address, to use the second we'll mark packets with the other address. The default rule is any: it will be executed the stack IPv* and the routing table default rule. --- Mozilla/5.0 (Windows; U; Windows NT 5.1; sv-SE; rv:1.9.1.16) Gecko/20101125 * Origin: news://felten.yi.org (2:203/2) .