From owner-biophysics@net.bio.net Sun Jan 25 22:00:00 1998 Path: biosci!bcm.tmc.edu!news.msfc.nasa.gov!europa.clark.net!152.158.16.55!newsfeed2.uk.ibm.net!news.ibm.net.il!ibm.net!news.biu.ac.il!news.huji.ac.il!not-for-mail From: "Jonathan B. Marder" Newsgroups: bionet.biophysics Subject: Re: Chemiosmotic events Date: Mon, 26 Jan 1998 11:26:50 +0200 Organization: Hebrew University Lines: 29 Message-ID: <6ahksq$nk0$1@news.huji.ac.il> References: <6a08ao$hov@mserv1.dl.ac.uk> NNTP-Posting-Host: marder.agri.huji.ac.il Mime-Version: 1.0 Content-Type: text/plain; charset="utf-7" Content-Transfer-Encoding: quoted-printable X-Newsreader: Microsoft Outlook Express 4.72.2106.4 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.2106.4 Pentcho Valev wrote in message = +ADw-6a08ao+ACQ-hov+AEA-mserv1.dl.ac.uk+AD4-... ... +AD4-Let us imagine two adjacent spots on the membrane: +AD4- +AD4--------------low-capacitance------high-capacitance------------------= ---- +AD4- +AD4-For the transmembrane potential difference to be the same across = the two +AD4-spots, the surface charge density (of H and the respective = counterion) +AD4-must be different. But this is extraordinary - consider only H on = one side +AD4-of the membrane - we have, laterally, a constant potential but a H +AD4-concentration gradient, i.e. we can expect a lateral H flow at = equilibrium. +AD4-What do you think? I would say that any lateral concentration gradient will be=20 offset by a lateral electrical potential gradient. Thus the lateral proton-motive force would be zero. Regards, Jonathan .