Subj : E4X: Filtering Predicate Operator
To   : netscape.public.mozilla.jseng
From : McKinley, Richard
Date : Mon Aug 23 2004 07:23 pm

I have tried this two different ways.  The following code matches the 
examples in section 11.2.4 very closely.  The results I want are all 
nodes with a level of 1:
           <node level="1">
             <node level="2"/>
             <node level="2"/>
           </node>
           <node level="1">
             <node level="2">
               <node level="3"/>
             </node>
           </node>
See the code below.  Why am I only getting the first node with level="1"?



   var tree =  <tree>
         <node level="0">
           <node level="1">
             <node level="2"/>
             <node level="2"/>
           </node>
           <node level="1">
             <node level="2">
               <node level="3"/>
             </node>
           </node>
         </node>
       </tree>;
   var nodesWithFilteringPredicateOperator = tree..node.(@level == 1);
   out.println(nodesWithFilteringPredicateOperator.toXMLString());
   /* output:
   <node level="1">
     <node level="2"/>
     <node level="2"/>
   </node>
   */

   var nodesWithForEach = new XMLList();
   var i = 0;
   for each(var n in tree..node) {
     with(n) {
       if(@level == 1) {
         nodesWithForEach[i++] = n;
       }
     }
   }
   out.println(nodesWithForEach.toXMLString());
   /*output:
   <node level="1">
     <node level="2"/>
     <node level="2"/>
   </node>
   */

Thanks,

McKinley

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