Subj : Re: Problem using rhino under java
To   : netscape.public.mozilla.jseng
From : Danilo
Date : Tue May 04 2004 01:43 pm

Igor Bukanov wrote:

> Danilo wrote:
>> Hi,
>> I have this problem:
>> 
>> JAVA:
>> 
>> class one{
>> 
>>         public Integer ret(){
>>                 return new Integer(12);
>>         }
>> }
>> 
>> 
>> Context cx = Context.enter();
>> try {
>>         Scriptable scope = cx.initStandardObjects();
>>         one o = new one();
>>         Scriptable jsarg = Context.toObject(o,scope);
>>         scope.put("o",scope,jsarg);
>>         s=<JSCODE SEE DOWN>
>>         try {
>>                 Object result = cx.evaluateString(scope, s, "<cmd>", 1,
>>                 null);
>>         }catch (JavaScriptException ex) {
>>           
>>         } catch (Exception ee){
>>            
>>         }
>> } catch (Exception ee){
>>           
>> } finally {
>>           cx.exit();
>> }
>> 
>>        
>>       
>>       
>> JAVASCRIPT
>> 
>> var x=3
>> x= x + o.ret()
>> getWrapFactory()
>> 
>> the problem is that x value is "312" instead of 15.
>> why interpreted o.ret() as String instead of Integer?
> 
> If you change "one"  into
> 
> class one{
> 
>          public int ret(){
>                  return 12;
>          }
> }
> 
> then it should work as expected.
> 
> The problem is that by default in Rhino a Java object is always
> represented by a special wrapper even if the object is a "boxed"
> primitive type. When such wrapper is present on any side of "+", it
> forces string context for "+" that gives "312" in your example.
> 
> You can disable this wrapping of boxed values if you change
> 
> Context cx = Context.enter();
> try {
>      ....
> 
> into
> 
> Context cx = Context.enter();
> try {
>      cx.getWrapFactory().setJavaPrimitiveWrap(false);
>      ....
> 
> 
> Regards, Igor

-- 


THANKS IGOR  

IT'S OK

.