Subj : new operator and call operator
To   : netscape.public.mozilla.jseng
From : =?ISO-8859-1?Q?Georg_Maa=DF?= <georg@vnett.de>
Date : Wed Mar 26 2003 07:28 am

Selection();
          ~~
That is a call operator.

new Selection;
~~~
Here is a new operator.

new Selection();
              ~~
But what ist that? Is that a call operator to be used for an internal 
call of the constructor function inside the new operation, or is that a 
part of a second variation of the new operator?

Are there two new operators?

new FUNCTION
and
new FUNCTION (OPERANDLIST)
where OPERANDLIST is used as arguments for the constructor function?

I ask this for correctly documenting the language. Should I speak about 
two new operator variation or should I speak about a pure new operator 
and a combination of new operator and call operator?

Experiments with Selection in the Mozilla browser let me think it might 
be better to speak about two new operator variations, because

Selection();

results in an error message, where

new Selection();
and also
new Selection;

results in an exception. This gives me the idea, that there is no "call 
operator" in the second sample but the () must be a part of the new 
operator, which causes me to say, that there are two new operators, one 
with () and an other without, both doing the same.

.