Subj : Re: Finding a set of numbers within a String
To   : comp.programming
From : pemo
Date : Mon Oct 10 2005 02:50 pm

You could use the Split function - something like this:

dim s as string: s = "1. 45.7j.L9"
dim slast as string

dim sa() as string

sa = split(s, ".")

slast = sa(ubound(sa)) <- might need a -1 there?

BTW, you say these values are hex, but j, L, g etc aren't valid?

"RayKnight" <rayknightro@yahoo.com> wrote in message 
news:4664c180bb1caf9aa11217d5d8903359@localhost.talkaboutprogramming.com...
> Lets say I have a set of randomly generated hexadecimal numbers. Say...
>
> 1. 45.7j.L9
> 2. 51.3g.D4
> 3. 67.99.62
>
> I want to find out the last two numbers of the randomly generated
> hexadecimal numbers. How do I do that? I know in C++, you can simply
> use...
>
> string monkey = "dynamic" ;
> if (monkey[2] == "n" && monkey[3] == "a")
> {
>     etc etc ;
> }
>
> But is there such a function in Visual Basic? I heard of a command using
> *, but is there a reference or anything I can use?
>
> References and links would be helpful, thank you.
>

.