Subj : Re: Question
To   : comp.programming
From : DarkD
Date : Sun Oct 02 2005 12:22 pm


"Bill Cunningham" <nospam@nspam.com> wrote in message
news:VGD_e.10558$kH3.986@trnddc01...
>
> > For a meaningful answer you'll need to say what hardware you're using,
> > what OS and what you expect to find at 0x00c0.  On a Commodore 64 using
> > the standard BASIC and KERNEL ROMs for example, that would be CAS1, the
> > tape motor interlock.
> >
> > Dave.
>
>     Win98 and xp. And linux OSs. 0x0c is what I'm looking for for the
> beginning of the partition table. Somewhere in there is the part signature
> for the partition and the mbr and filesystem signature. C being the
> signature for win95 LBA and 6 being FAT16. Why in the code above did you
> make x a pointer to an int and not declare x as an int? Do you not want x
to
> be assigned any value?

Im not sure you fully understand a pointer. He is pointing to that memory
location and displaying the integer value from that location. If you did
this:

int x;
x = *&0x00c0;
printf("Value at address 0x00c0 is %d\n",x);

You would be copying the integer value at the location into x, and then
displaying x.

In his instance x is a pointer and is assigned the the address 0x00c0, in my
instance x is an integer and is assigned the value at the address 0x00c0.

.