Subj : Re: overflow in C
To   : comp.programming
From : DarkD
Date : Wed Sep 21 2005 11:07 pm

C99 says its 'undefined behavoiur' if its signed. This is because a computer
could be using one's compliment or two's compliement, or even ignores the
most significant bit. A compiler is allowed to error on this (and should),
alot ignore it.

For unsigned a modulo is performed with the max number of values, so a char
set to 257 will be 1.
> signed char a = 130;
>
> I explicitly generate an overflow since the maximum value a singned char
> can accommodate is "127". Is this behavior of the overflow defined in any
> way or do I get an undefined state of "a" due to the C standards?

.