Subj : Re: bit shifting
To   : comp.programming
From : Rob Somers
Date : Sun Aug 14 2005 01:15 pm

>>   unsigned short x = 128;
>>   unsigned short y = 255;
>>
>>   printf("%u\n", (unsigned short)(~x & y));
>>   printf("%u\n", (unsigned short) ~x);
>>
>>   return 0;
>> }
>>
>> if 127 is 1111111 and 255 11111111, then &ing the two should give
>> 01111111.
> 
> Yes, but the above apparently computes 0xff7f & 0xff.
> 
>> Why does the second printf() give 65407?
> 
> What did you expect it to give?
> 
> Alex

Sorry, I was in a rush when I asked my question.  I am not understanding
what the difference between the 1111111 (127) and 01111111 (from 127 & 255)
- obviously 1111111 is not 01111111, but I thought the leading 0 did not
count for anything.

.