Subj : Re: Faster matrix permutation algorithm? To : comp.lang.c,comp.programming From : Richard Heathfield Date : Sat Aug 13 2005 02:02 pm [Followups set to comp.programming] Jack Middleton wrote: > Hi! > > I'm lookin for a faster permutation algorithm for matrices. I know that > it can be done with multiplying a matrix with a permutation matrix. It > just seems a waste to iterate through all those zeroes. Is there an > algorithm for matrixes that is optimized just for permutations? The > matrices that I use are fairly small (around 6*6) and I only use > positive integers as elements. Consider a mapping between a matrix X * Y elements in size and a series of numbers from 0 to X * Y - 1. Such a mapping is reversible. To map from the matrix cell references to a single number, use: m = x * Y + y; To map from the single number to cell references, use: x = (m - y) / Y; y = m % Y; Set up a list of single numbers, 0 to X * Y - 1, in an array, and permute the array, using the normal recursive technique. T is some (sensible) assignable type. Perm is a pointer to the first element in an array of n elements of type T. The final parameter, 'unchanged', is set to 0 in the initial call: void Permute(T *Perm, size_t n, size_t unchanged) { size_t outer = 0; size_t inner = 0; T temp = 0; if(unchanged < n) { for(outer = unchanged; outer < n; outer++) { temp = Perm[outer]; for(inner = outer; inner > unchanged; inner--) { Perm[inner] = Perm[inner - 1]; } Perm[unchanged] = temp; Permute(Perm, n, unchanged + 1); for(inner = unchanged; inner < outer; inner++) { Perm[inner] = Perm[inner + 1]; } Perm[outer] = temp; } } else { /* Perm[0] through Perm[n - 1] now form a permutation. * If T is char, Perm points to a modifiable string * containing the three letters 'a', 'b', 'c', n is 3, and * unchanged is initially 0, then this else-block will be * visited six times, and a printf("%s\n", Perm); at this * point will write each of the six possible permutations, * one per visit. */ } } Call this once, and it will do all your permutations for you. By making T int, you can get a simple correspondence between the array and your matrix. If you're feeling really brave, you could modify Permute() to talk to your matrix directly, using the mapping I suggested earlier. -- Richard Heathfield "Usenet is a strange place" - dmr 29/7/1999 http://www.cpax.org.uk mail: rjh at above domain .