Subj : Re: simple c/c++ programming question about encryption
To   : comp.programming
From : Sc0rpi0
Date : Tue Jul 05 2005 05:03 am

> [...] It goes through the code one full
> time (and updates the counter) before asking for user input - thus it
> updates the counter twice for every one input.  Since I'm not so
> familiar with C, can anyone explain this to me.  The same program works
> perfectly with C++, which is why I don't understand this.

>    scanf("%c", &originalLetter);
> 
>    if(originalLetter >= '!' && originalLetter <= '~' && k < 93 && k >=
> 0){
>      encryptedLetter = BASE+(originalLetter-BASE+k)%RANGE;/*the
> calculation*/
>      printf("The encrypted character is %c.\n", encryptedLetter);
> /*Output */
>    }
>     counter = counter + 1;

Because scanf reads '\n' characters (end of line) from previous
inputs, so you're getting '\n',user_input,'\n',user_input, etc.
'\n' usually is <'!' - encryption does not catch that, but counter
is updated. In C++ you use streams so it is not reading the chars
the same way as in C and program is NOT THE SAME ;)


-- 
Sc0rpi0
I hated going to weddings.
All the grandmas would poke me saying "You're next".
They stopped that when I started doing it to them at funerals.

.