Subj : Re: Really **wonderful** website for C interview questions!!!!!
To   : comp.programming
From : Robert Bunn
Date : Sun Jul 03 2005 05:58 pm


"Alan Morgan" <amorgan@xenon.Stanford.EDU> wrote in message
news:d9eump$28u$1@xenon.Stanford.EDU...
> In article <42baa97c$0$22622$da0feed9@news.zen.co.uk>,
> Joe Butler <ffffh.no.spam@hotmail-spammers-paradise.com> wrote:
> >Oooookaaaaay...
> >
> >I'm not a novice, but at risk of being labelled one, I'm looking at
x= !!y
> >wondering...
> >
> >I'd assume that !! would be interpreted as NOT NOT and have the
effect of
> >turning any non-zero integer number into a 1, and leaving 0 as 0. ??
>
> Yup.  The basic problem is that two true values might not compare
equal to
> one another because all non-zero values are true.  Using !! ensures
that true
> values will compare equal to one another.
>

Okay. I guess I *am* a novice. How is

if(x == (!!y) )
any more useful (or clear) than

if(x && y)

?

Or am I misinterpreting your statement *very* badly indeed?

--
Rob

.