Subj : Re: I need a routine to convert a real48 type into a double
To   : borland.public.cpp.borlandcpp
From : Ed Mulroy
Date : Tue Aug 02 2005 08:44 am

See if this does the trick:
http://orion.planet.de/~jan/Snippets.9707/_d0903.html

Your program is a 32 bit one and elements in a structure are aligned on 32 
bit or 4-byte boundaries.  You are reading in a packed structure, a 
structure aligned on 8 bit or 1-byte boundaries.  To do that you must 
specify a packing size of 1 byte.

    #pragma pack(1) /* set 1-byte alignment */

    struct TMyCBuilderStruct  {
    unsigned char aReal48Value[6];
    unsigned char aByteValue;
    unsiged short aWordValue;
    and so on...
    };

#pragma pack() /* restore the original alignment */


Note that your question is about C++ Builder.  However you have posted it 
here, in the newsgroup for the old Borland C++ compiler.

Please post questions in newsgroups where what you are asking about is the 
expected subject.  You can identify which newsgroups are for C++ Builder by 
the word 'cppbuilder' in their name.

..  Ed

> E. Kali wrote in message
> news:42ef32d4$1@newsgroups.borland.com...
>
> I've got the following problem. I'm reading data out of a binary file 
> which had been written by a Delphi application.
> The data structure of the delphi application which wrote the data looks 
> like this-->
>
> TMyDelphiRecord = packed record
>  aReal48Value   : Real48;
>  aByteValue   : Byte;
>  aWordValue : Word;
>  and so on...
> end;
>
> My C++ Builder application reads the into a data structure like this
>
> struct TMyCBuilderStruct{
>  unsigned char aReal48Value[6];
>  unsigned char aByteValue;
>  unsiged short aWordValue;
>  and so on...
> };
>
> My question ==> how can I convert the aReal48Value into a valid c++ double 
> value?.

.