Subj : Re: Dynamic Array Initialization
To   : borland.public.cpp.borlandcpp
From : maeder
Date : Mon Mar 28 2005 10:47 am

"kvgs" <atsoumpalos@yahoo.gr> writes:

> int *Bets;
> Bets     = new int [10];

Side note: better intialize variables in their definition. It's much
easier to get/keep code correct that way. E.g.:

int *Bets(new int[10]);

Better yet, use a container object, such as a vector<int>.


> Bets[10] = {1,2,3,4,5,6,7,8,9,10};

The expression Bets[10] is (an l-value) of type int.

First, you can't assign it anything that is not convertible to int.

Second, the curly braces syntax on the right side of the assignment
operator is only allowed in aggregate initializations. This is an
assignment, though, not an initialization.


> for (int i=0; i<10; i++)
>    ShowMessage(IntToStr(Bets[i]));
> delete[] Bets;
>
> If I do this instead and don't use a dynamic array, everything is
> ok
>
> int Bets[10] = {1,2,3,4,5,6,7,8,9,10};

Here you are using aggregate initialization to initialize the
array. Aggregate initialization can only be used to initialize, uuh,
aggregates. Aggregates include structs, unions, arrays of static and
automatic storage duration, but not dynamically allocated arrays.


Elements of dynamically allocated arrays can't be initialized. To give
them their desired values, you have to assign to them after the
allocation.

To assign values to the elements of the dynamically allocated array,
use either a for loop or an appropriate Standard C++ Library
algorithm.

.