Subj : Any help on why?
To   : borland.public.cpp.borlandcpp
From : Stan DeGroff
Date : Tue Jul 06 2004 09:58 pm

The following example was from Sams Learning C in 24hrs.
-------------------------
#include <stdio>
#include <stdarg>

double AddDouble(int x, ...);

main()
{
 double d1 = 1.5;
   double d2 = 2.5;
   double d3 = 3.5;
   double d4 = 4.5;

   printf("GIven an argument: %2.1f\n", d1);
   printf("The result returned bu AddDouble() is: %2.1f\n\n", AddDouble(1,
d1));

   printf("Given arguments: %2.1f and %2.1f\n", d1, d2);
   printf("The result returned by AddDouble() is %2.1f\n\n", AddDouble(2,
d1, d2));

   printf("Given arguments: %2.1f, %2.1f and %2.1f\n", d1, d2, d3);
   printf("The result returned by AddDouble() is %2.1f\n\n", AddDouble(3,
d1, d2, d3));

   printf("Given arguments: %2.1f, %2.1f, %2.1f and %2.1f\n", d1, d2, d3,
d4);
   printf("The result returned by AddDouble() is %2.1f\n\n", AddDouble(4,
d1, d2, d3, d4));
 return 0;
}

/* Definition of AddDouble() */
double AddDouble(int x, ...)
{
 va_list arglist;
   int i;
  double xresult;
   double result = 0.0;


   printf("The number of arguments is : %d\n", x);
   va_start(arglist, x);
   for (i=0; i<x; i++){
      xresult = double va_arg(arglist, double);
    result += xresult;
      printf("%d  %X, %X\n", i, xresult, result);
   }
   va_end(arglist);
   return result;
}
-------------------------------------------------
I was having problems getting the results.  However, I found the mistake and
it now works.
BUT...  In the process, I found by putting in some printf statements to aid
in debug, That prints the
variable "xresult" resulted in printing 0x0000. However the variable
"result" printed ok.  Any ideas why the compiler forgets xresult?

Thanks
Stan DeGroff

.