Subj : Re: STL stack.pop() question
To   : borland.public.cpp.borlandcpp
From : maeder
Date : Tue Jun 29 2004 07:39 pm

KonZa <spam_me@operamail.com> writes:

> sorry if this is not the appropiate place to post this..but its short
> anyway..

If you are using Bolrland C++, then you are right here. But please have
a look at http://info.borland.com/newsgroups/ and read the newsgroup
descriptions and guidelines before your next post, even if it's a short
one again. This will help you find the appropriate newsgroup.


> stack<employee> my_stack;
>
> my_stack.push(employee("john1"));
> my_stack.push(employee("john2"));
>
> employee i = my_stack.top();
> my_stack.pop();
> my_stack.pop();
>
> My question is how 'i' is assigned to the top of the stack since the
> 'top'  method return a reference. what is the mechanism here? copy
> constructor?

i is never assigned in this snippet. It's just initialized on the line of its
definition; it will be destructed once it goes out of scope.

The initialization of i takes a reference to employee as its argument.
This means that the employee copy constructor will be used to initialize i.

.