Subj : Re: Windows Prompt Runtimes SHORT-Debug
To   : borland.public.cpp.borlandcpp
From : Ed Mulroy [TeamB]
Date : Mon Jun 21 2004 12:17 pm

What do you mean by "runs short"?

If you mean that the program runs quickly, of course it does.  Your
program has very little in it.

There is an error in what you show, this line is wrong
   #include <stdio.h><conio.h>

If you want to include both files then you need to do so individually
like this:
  #include <stdio.h>
  #include <conio.h>

And if you are not using getch() then why are you including conio.h?

There also is another error in the program, a logical error.  You used
scanf but did not use it correctly.  The function stops at the last
character which meets its input specification, leaving the following
character in the input buffer.  That following character is the enter
key.  When you called getchar() , it did what it was told, read the
remaining character.  You either must read in that character before
doing more input or handle it in some other way.

That is part of the reason that the function sscanf is more commonly
used instead of scanf.  It does not share this behavior.

Here are two versions of your program, both of which work.  The second
uses sscanf.  Both also show the return type for main as the default
of 'int' has been removed from the language specification.  Both use
an 'else' on mutually exclusive 'if' statements.  Both change the two
initial 'printf' calls which are used to write one prompt to one call
because the second is not needed.

----using scanf------------------
  #include <stdio.h>

  int main()
  {
  int num1, num2;

  printf("Enter two integers, and I will tell you\n"
     "the relationships they satisfy: ");
  scanf("%d%d", &num1, &num2);

  if (num1 == num2)
     printf("%d is equal to %d\n", num1, num2);
  else if (num1 != num2)
     printf("%d is not equal to %d\n", num1, num2);

  if (num1 < num2)
     printf("%d is less than %d\n", num1, num2);
  else if (num1 > num2)
     printf("%d is greater than %d\n", num1, num2);

  if (num1 <= num2)
     printf("%d is less than or equal to %d\n", num1, num2);

  if (num1 >= num2)
     printf("%d is greater than or equal to %d\n", num1, num2);

  getchar(); /* swallow the '\n' that scanf left in the input buffer
*/
  printf("Press enter...");
  getchar();
  return 0;
  }

----using sscanf------------------
  #include <stdio.h>

  int main()
  {
  int num1, num2;
  char input_buffer[133];

  printf("Enter two integers, and I will tell you\n"
     "the relationships they satisfy: ");
  fgets(input_buffer, sizeof(input_buffer), stdin); /* read input */
  sscanf(input_buffer, "%d%d", &num1, &num2); /* scan it */

  if (num1 == num2)
     printf("%d is equal to %d\n", num1, num2);
  else if (num1 != num2)
     printf("%d is not equal to %d\n", num1, num2);

  if (num1 < num2)
     printf("%d is less than %d\n", num1, num2);
  else if (num1 > num2)
     printf("%d is greater than %d\n", num1, num2);

  if (num1 <= num2)
     printf("%d is less than or equal to %d\n", num1, num2);

  if (num1 >= num2)
     printf("%d is greater than or equal to %d\n", num1, num2);

  printf("Press enter...");
  getchar();
  return 0;
  }
----------------------

..  Ed

> Jeremy Pham wrote in message
> news:40d6dbaf$1@newsgroups.borland.com...
>
> Man, too bad I'm not expert.  I did some revisions and prompt is
> still short.  I'll need help revising.  Here's the first program:
....

.