Subj : Re: multi-dimensional array/pointer help
To   : borland.public.cpp.borlandcpp
From : Bob Gonder <notbg@notmindspring.invalid>
Date : Fri Apr 09 2004 02:35 am

detritus wrote:

>What I would like to do is pass an elements such as char *num[2][2] to a
>function that is not constrained by the size of the array num.
>
>for example, what I was hoping would work is this:
>
>/* function prototype */
>void fun(char ***ptr);  /* what this dose dosen't realy matter */
>
>char *num[2][2] =  {{"One","Two"},{"Three","Four"}}; /* initialize the array
>*/
>
>fun(num); /* use fun to do something with the array */
>
>
>So how do I go about that?

First, it would be
/* function prototype */
void fun(char **ptr);
It doesn't matter how many [ ] you have, they only account for One *
(the char* is the other one).

Second, the function "fun" sees the array as single dimension.
You could do
void fun( char**ptr, int one,  int two)
{
	for( i=0; i<one; i++ )
	for( k=0; i<two; j++ )
		cputs( ptr[ ( i*two)+j ]  );
This is the same code that the compiler uses for ptr[ i ][ j ], but
you can't use [][] in "fun" because the compiler doesn't know the
dimension of the second (or third or fourth...) [ ].

}

	fun( num, 2, 2 );

.