Subj : Re: multi-dimensional array/pointer help
To   : borland.public.cpp.borlandcpp
From : "detritus" <thelovells@froggy.com.au>
Date : Fri Apr 09 2004 07:52 pm

I get the gist of what you are saying.

What I would like to do is pass an elements such as char *num[2][2] to a
function that is not constrained by the size of the array num.

for example, what I was hoping would work is this:

/* function prototype */
void fun(char ***ptr);  /* what this dose dosen't realy matter */

char *num[2][2] =  {{"One","Two"},{"Three","Four"}}; /* initialize the array
*/

fun(num); /* use fun to do something with the array */


So how do I go about that?

"Bob Gonder" <notbg@notmindspring.invalid> wrote in message
news:pn1c705f5gq7rlhdbku1s440iosgmf49g2@4ax.com...
> detritus wrote:
>
> >It should read :
> >
> >> int main()
> >> {
> >>   char *num[2][2] = {{"One","Two"},{"Three","Four"}};
> >>   char ***numPtr;
> >>   numPtr = num;
> >>   return 0;
> >> }
> >
> >What I would like to know is why the following code works and the above
> >dosent:
>
> Too many **s.
> If you say char num[2];
> Then "num" is a char*
> If you say char two[2][3];
> Then "two" is still a char*
> If you say char*num[2][2];
> Then "num" is a char**
> Trying to put a char** into a char*** doesn't work.
> That's why the below code works and the above doesn't. Nothing to do
> with the extra[] or "Three","Four" parts.
> "num" contains 4 pointers to char, not 4 pointers to pointers to char.
>
> >int main()
> >{
> >  char *num2[2] = {"One","Two"};
> >  char **num2Ptr;
> >  num2Ptr = num2;
> >  return 0;
> >}
>

.