Subj : Re: Precedence...
To   : borland.public.cpp.borlandcpp
From : "Ed Mulroy [TeamB]" <dont_email_me@bitbuc.ket>
Date : Wed Mar 17 2004 06:07 pm

That is correct behavior.

Post increment means the value used of the variable in the expression
is the original value.  The saved value of the item ('s' in this case)
is incremented.

  --------------------
  char *s = "test";
  char c;

  c = *s++;  c = *s;  c = *(s++); all result in c == 't'
  c = *++s;  c = *(s += 1); c = *(++s); all result in c == 'e'
  --------------------

..  Ed

> Joćo Henrique wrote in message
> news:4058d731@newsgroups.borland.com...
>
> Why this happens?
>
>     char *s = "test";
>     char  c = *(s++); // The c value is 't', not 'e'. Why?
> Compiler optmization?

.