Subj : Memory Management,. C Vs C++
To   : borland.public.cpp.borlandcpp
From : "Rob C. " <robb_christiansen@juno.com>
Date : Sun Nov 16 2003 10:59 am


Correct me if I’m wrong. 

In straight C - You have an array of 5000 pointers to int, 
[ int *ArrayName[5000];  ], which takes up . . . what, 5000?, 
6000? bytes of memory. Each pointer/sub represents a node , 
[ say, ArrayName[sub] = (int *) malloc( sizeof( int ) ); ]. 
Okay, so now, when you’re all done with the array of pointers, 
you can free-up the 5000 nodes and recapture that much memory, 
but the 5000?, 6000? bytes used by the array are still in use
and thus still inaccessible.

But now in C++ - You have the same array of 5000 pointers to 
int. Each pointer/sub represents a node. This time, however, you 
declare the array to be a member of an object. Like before, when 
you’re all done with the array of pointers, you free-up the 5000 
nodes and recapture that much memory, but then simply delete the 
object, thus recapturing the additional 5000?, 6000? bytes used 
by the array, for other purposes.

Is this right? [ Would you even have to “free” or “delete” the 
nodes, or would that be automatically done for you when you 
deleted the object? ]

.