Subj : Help with an opcode
To   : Michael Preslar
From : Roelof Beverdam
Date : Wed Nov 09 2005 11:48 pm

Hello Michael,

 > As I work my way through some older code, Im converting inline() statements
 > to assembler. I've found one that I dont quite understand.
 >
 > inline($06/$1f)    (* mov ds, es *)
 >
 > Now.. Ive tried the "mov ds, es" bit (And after being reminded that es is
 > the way to access variables) I see that the "mov" is incorrect.

Yep.

Although effectively the same as suggested by the comment, the actaul 
instructions are different.

  $06 = push es
  $1F = pop ds

Grasp the trick? ;-)

Use these 2 instructions and your assembler will be happy.

Cheers,
Roelof Beverdam

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