Subj : Encoder in C...
To   : Frank Reid
From : Angus Mcleod
Date : Thu Dec 02 2004 09:00 am

Here's a quick'n'dirty attempt at an encoder:

  #include <stdio.h>
  #include <string.h>

  int main( int argc, char **argv ) {
      char *p, *q, *allowed = "-_.!~*'()";

      argv++;         	// skip argv[0]
      while (*argv) {
          p = *argv;
          while (*p) {
            if (((*p >= '0') && (*p <= '9')) ||         // digit
                ((*p >= 'A') && (*p <= 'Z')) ||         // upper case
                ((*p >= 'a') && (*p <= 'z')) ||         // lower case
                (strchr( allowed, *p ) != NULL)) {      // allowed
                    putchar( *p++ );
            } else
                printf( "%%%02X", *p++ );       // char must be encoded
            }
            argv++;
      }
      putchar( '\n' );
      return 0;
}

I'd have preferred to build up the result in a buffer and then done a 
single puts() at the end, but then the question of how big a buffer is 
adequate raises it's ugly head.....

Is there a way to fill the char *allowed array with the UC and LC alphabet 
and the list of digits with*OUT* typing them out in full?  It would 
simplify the if() condition considerably.


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