Subj : How to detect RAM disks (Was: how to detect cdrom?)
To   : Jasen Betts
From : Gerald Miller
Date : Thu Feb 28 2002 07:34 am

From: Gerald.Miller@f512.n342.z1.cereal.mv.com (Gerald Miller)
Subject: How to detect RAM disks (Was: how to detect cdrom?)

Hello Jasen,

  Wednesday February 27 2002 06:39,
  Jasen Betts wrote to Gerald Miller:

 GM>>       mem /module ramdrive > MEM.OUT

 GM>> Can the command: mem /module %module_name not provide the
 GM>> information that you are seeking?

 JB> you neeed to know the name of ramdrive module...
 JB> (it could be vdisk intead of ramdrive etc....)

 JB> also  it doesn't tell what drive letter...

 GM>> I can type:

 JB>       mem /c >> E:\Tmp\MOD_NAME.DAT

 GM>> I can get a list of memory modules and with a little creative
 GM>> editing, I can get a list of module_names and should be able to
 GM>> use the edited list as input to a command:

 GM>>       for %%mod in (at e:\tmp\mod_name.dat) do call mem /module
 GM>> %mod

 GM>> and I can see all the installed devices with other information...
 GM>> which brings me to the following point:

 GM>> Can you not take a previously created MOD_NAME.DAT file and use
 GM>> it as imput to test for other installed devices?

 JB> yeah... but it still won't give the drive letter.
 JB> (you need mem /d)
 JB> and it also relies on knowing the name of the ramdisk program.

How is "MEM /D" able to determine the name of the ramdisk
program?

First - Determine if a device is installed.

Second - Determine the name of the device (should be able to
         deduce the manufacturer / author / version)

When you know a device is installed and you know the name, then
you should be able to conduct the test for a drive letter.  From
what I've been able to determine, you are likely to get "false
positive" results if you test for the presence of a label and I
was trying to bring that fact to attention.

If someone can determine how MEM /D hooks into the memory to
determine the name of the ramdisk program (and the drive letter),
then you /_may_/ have the basis for the utility.

           Cheers ... Gerald
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