X-Google-Language: ENGLISH,ASCII X-Google-Thread: f996b,6812b58dfe61342e X-Google-Attributes: gidf996b,public X-Google-ArrivalTime: 2001-12-03 09:59:07 PST Path: archiver1.google.com!news1.google.com!sn-xit-02!supernews.com!news.tele.dk!small.news.tele.dk!130.133.1.3!fu-berlin.de!uni-berlin.de!46.137.hh1.ip.foni.NET!not-for-mail From: Philip Newton Newsgroups: alt.ascii-art Subject: Re: How can I solve this @#%#@%^#@$&^%*$%#@@#! Date: Mon, 03 Dec 2001 19:02:39 +0100 Organization: very little Lines: 17 Message-ID: References: <3bf81b34$0$9953$626a54ce@news.free.fr> <9ud9ig$iqt$01$1@news.t-online.com> Reply-To: "Philip 'Yes, that's my address' Newton" NNTP-Posting-Host: 46.137.hh1.ip.foni.net (212.7.137.46) Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: 8bit X-Trace: fu-berlin.de 1007402345 8768000 212.7.137.46 (16 [11583]) X-Newsreader: Forte Agent 1.8/32.548 Xref: archiver1.google.com alt.ascii-art:12117 On Sun, 2 Dec 2001 00:01:07 +0100, "Johannes 'Joey' R�ssel" wrote: > you then get a value for x and then you just go on calculating. By the 15th > time the value shouldn't change anymore. But if there is more than one solution, you only get one. And for best results, your initial value (1, in this case) should be close to one of the solutions. Cheers, Philip -- Philip Newton That really is my address; no need to remove anything to reply. If you're not part of the solution, you're part of the precipitate.