X-Google-Language: ENGLISH,ASCII
X-Google-Thread: f996b,8d14db4b24713566
X-Google-Attributes: gidf996b,public
From: Veronica Karlsson <e93-vkn@sm.luth.se.nospam>
Subject: Re: Looking for Chart of Ascii Characters
Date: 1997/05/04
Message-ID: <336C6ED8.167EB0E7@sm.luth.se.nospam>#1/1
X-Deja-AN: 239330890
References: <5khf5c$h31@reader.seed.net.tw>
Organization: University of Lulea, Sweden
Newsgroups: alt.ascii-art


> 
> JeePster (sbaerman@erols.com) wrote --
> 
> > I am in search of a chart that gives a list of all possible characters
> > within the text realm as well as the Exact keyboard input required to
> > achieve this. An example of this would be a square � . I stumbled on
> > this by chance. The keyboard input to achieve the � is 0911 with the ALT
> > key held down. I have seen quite a few others such as a tre' kewl smiley
> > face and a heart but I have yet to discover the required typing need to
> > produce them.
>


Why not try the simple approach and write a small program that will go
through the numbers 0 to 255 (or 127) and try to write them both as
numbers and as characters and see what happens...


I have written a small C program that does that (how you compile it is
different on different computers. On the unix system here at my school I
write  gcc program_name.c -o program_name )


[begin C program code example 1]

#include <stdlib.h>
#include <stdio.h>

main()
{
  int i;

  for (i = 0; i <= 255; i++)
    {  printf("%d  %c\n", i, i);
    }
}

[end C program code example 1]




If you prefer to have the numbers as hexadecimal instead of decimal you
can use this code:


[begin C program code example 2]

#include <stdlib.h>
#include <stdio.h>

main()
{
  int i;

  for (i = 0; i <= 255; i++)
    {  printf("%0x  %c\n", i, i);
    }
}

[end C program code example 2]




(after a couple of tries you may find it necessary to "screen out" some
numbers by "counting past" them. In the example below I have screened
out number 15:



[begin C program code example 3]

#include <stdlib.h>
#include <stdio.h>

main()
{
  int i;

  for (i = 0; i <= 255; i++)
    { if (i == 15) i++;         /* don't show number 15 */
      printf("%d  %c\n", i, i);
    }
}
     
[end C program code example 3]

when I run this the program will show the numbers ...13, 14, 16, 17...)



I hope this helps.

-- 
:)
Veronica Karlsson
( e93-vkn@sm.luth.se  http://www.ludd.luth.se/~vk/ )
( llizard's animation site:  http://jota.sm.luth.se:80/~e93-vkn/docs/ )