X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 10c7e7,b2d59af78b44d574 X-Google-Attributes: gid10c7e7,public X-Google-Thread: f4928,b2d59af78b44d574 X-Google-Attributes: gidf4928,public X-Google-Thread: 108353,b2d59af78b44d574 X-Google-Attributes: gid108353,public X-Google-Thread: 112aef,b2d59af78b44d574 X-Google-Attributes: gid112aef,public X-Google-Thread: f996b,b2d59af78b44d574 X-Google-Attributes: gidf996b,public X-Google-Thread: f4ab8,b2d59af78b44d574 X-Google-Attributes: gidf4ab8,public X-Google-Thread: 10ed79,b2d59af78b44d574 X-Google-Attributes: gid10ed79,public From: Paul Wilkins Subject: Re: <><><><>Can ANYONE do this Math Problem, Please?<><><><> Date: 1996/08/17 Message-ID: <32149793.61E@tpnet.co.nz>#1/1 X-Deja-AN: 174575146 references: <4uveh4$lmu@tofu.alt.net> <3213CB3D.152D@midwest.net> content-type: text/plain; charset=us-ascii organization: tpNet, Christchurch, New Zealand mime-version: 1.0 newsgroups: alt.society.high-school,alt.teens,alt.teens.poetry.and.stuff,alt.poetry,alt.graphics,alt.ascii-art,alt.graphics.pixutils x-mailer: Mozilla 3.0b6Gold (Win95; I) Bill Risher wrote: > > Nobody In Particular wrote: > > > > //| / __ /_ __ __ / WANTS YOU AND YOUR CREATIVITY > > // | / / ) / ) / ) / / / / Social Computing 4-U*By-U*About-U > > // | / (__/ (__/ (__/ (__/ (__/ It's FREE! A way to fund the arts, > > // | / ___In Particular___ / Charity & YOU! Magazine & Tape Club > > // |/________________________/ > > > > Here's the problem: If you tell 2 people about our webpage, > ^-(guy 1 and 2,at point 1) > > and they each tell two people, and they > ^-(3,4,5,6,at 2) > > tell two people, and so on and so forth, > ^-(7,8,9,10,11,12,13,14,at 3) > > how many people would know after 20 times? > question: do guy 1 and 2 tell two more people at point 3? or do they > only tell 3-6 at point 2? > -- > _ _ _ _ _ ____ ____ _ __ ____ ___ billr1@midwest.net > | | | | |_| |_ _|__ | | / /|_ _| \ Of all the things I've > | | | | ._. |_||_ ,',' ==| < _||_| |) ) ever lost, I miss my > \_,_/|_| |_|____|____| |_\_\|____|___/ mind the most. It should be 2^(n+1)-2 Then when n=1, people = 2 n=2, people = 6 n=3, people = 14 etc... for 20 lots of this you'd end up with 1,048,574 people, presuming each one tells only 2 poeple who haven't been told before.